Question 649560: In a crowd of ninety people how many ways can ten digital players be given away
Answer by swincher4391(1107)   (Show Source):
You can put this solution on YOUR website! The digital players are indistinguishable, but people are. This problem is kind of like having 10 $1 bills and you want to give them to 90 people. Imagine you have 89 partitions between 90 people. Then we have ((90-1)+10) total things to choose from. We are choosing 89 partitions. So we have 99 choose 89 = 1.558 * 10^13.
----------------
The general rule is if there are permutations of sets (people in this case) with some indistinguishable objects (ten digital players), then there are C(n+k-1,k-1) ways to do this. Where we have n players and k people.
|
|
|
