You can put this solution on YOUR website! If you're supposed to factor:
You'll eventually want to memorize this:
This is a perfect square trinomial.
Happy Calculating!!!
You can put this solution on YOUR website!
To solve: (1) b^2-2bc+c^2=0 We will rewrite this equation to see if we can find factors:
b^2-bc+c^2-bc=0 and
b(b-c)+c(c-b)=0 which equals
b(b-c)-c(b-c)=0
(b-c)(b-c)=0
b-c=0
b=c
ck
substitute b=c in (1)
c^2-2c^2+c^2=0
2c^2-2c^2=0
0=0
Actually, you may be able to solve this problem (get the factors) by trial and error. We know what the factors of c^2 are: (-c)(-c) and (+c)(+c).
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