SOLUTION: Find the exact value of trig functions of theta
sin (theta) = - 3/7 given that theta is in quadrant IV
I don't understand how to rationalize the problem once I get to: cos
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sin (theta) = - 3/7 given that theta is in quadrant IV
I don't understand how to rationalize the problem once I get to: cos
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Question 649335: Find the exact value of trig functions of theta
sin (theta) = - 3/7 given that theta is in quadrant IV
I don't understand how to rationalize the problem once I get to: cos = the square root of 1 - 3/49 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the exact value of trig functions of theta
sin (theta) = - 3/7 given that theta is in quadrant IV
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You are working with a reference angle and right triangle in given quadrant IV
sin=opp side/hypotenuse=-3/7
adjacent side=√(7^2-3^2)=√(49-9)=√40
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Trig Functions:
sin theta=-3/7
cos theta=√40/7
tan theta=-3/√40=-(3√40)/40
csc theta=-7/3
sec theta=7/√40=(7√40)/40
cot theta=-√40/3
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