SOLUTION: A house has two rooms of equal area. One room is square and the other room is a rectangle 4ft narrower and 5ft linger then the square one. Find the area of each room.
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-> SOLUTION: A house has two rooms of equal area. One room is square and the other room is a rectangle 4ft narrower and 5ft linger then the square one. Find the area of each room.
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Question 64913This question is from textbook Algebra Structure and Method
: A house has two rooms of equal area. One room is square and the other room is a rectangle 4ft narrower and 5ft linger then the square one. Find the area of each room. This question is from textbook Algebra Structure and Method
You can put this solution on YOUR website! X^2=(X-4)(X+5)
X^2=X^2-4X+5X-20
0=X-20
X=20 FOR THE SIDES OF THE SQUARE ROOM THEN THE RECTANGLE ROOM IS
20-4=16 & 20+5=25
THE SQUARE ROOM HAS 20*20=400 SQUARE FEET
THE RECTANGLE ROOM HAS 16*25=400 SQUARE FEET
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