SOLUTION: Any help on this would be great, I can't seem to figure it out. A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of t

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Any help on this would be great, I can't seem to figure it out. A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of t      Log On

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Question 64898: Any help on this would be great, I can't seem to figure it out.
A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in2. What are the dimensions of the photo?

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(X+4)(X+7)=108
(X+4)IS THE WIDTH (X)+ TWO 2 INCH BORDERS
(X+7)IS THE LENGTH (X+3)+ TWO 2 INCH BORBERS
(X+4)(X+7)=108
X^2+11X+28=108
X^2+11X-80=0
(X+16)(X-5)=0
X+16=0
X=-16 (NON SOLUTION)
X-5=0
X=5 SOLUTION. INCHES FOR THE WIDTH OF THE PICTURE
X+3=8 INCHES FOR THE LENGTH OF THE PICTURE.