SOLUTION: The vertex form of the equation of a parabola is y=5(x-3)^2-6. What is the standard form of the equation

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Question 648925: The vertex form of the equation of a parabola is y=5(x-3)^2-6. What is the standard form of the equation
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

The vertex form of the equation of a parabola is 

y= 5(x-3)^2-6

y = 5(x^2-6x + 9) - 6

y = 5x^2 - 30x + 45 - 6

y = 5x^2 - 30x + 39

Check by completing the square

y = ax^2 + bx + c   ⇒ y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c

y = 5(x-3)^2 -45 + 39

y = 5(x-3)^2 -6