L has y-intercept (0, -3) and is parallel to
the line with equation y = (2/3)x + 1.
We compare the equation
y = (2/3)x + 1
to the slope-y-intercept formula
y = mx + b
and we can see that the slope is m = 2/3
and the y-intercept is (0,b) = (0,1)
A line parallel to that one has the same
slope, m = 2/3 but has a different
y-intercept, (0,b) = (0,-3), so its
equation must be
y = mx + b
y = (2/3)x - 3
(just like the original line's equation
but with a different value for b.
Edwin
