13 - 2/5 = H + 6 - 4/15
My daughter has just begun to take Pre-Alegbra
& we are seeking help in learning the proper to
understand equations. Thanks!
The terms on the left are
13 and -2/5
The terms on the right are
H, 6, and -4/15
The fraction terms are -2/5 and -4/15.
So we clear of fractions to make it easier:
We multiply every term on both sides by
their least common denominator, 15. So we write
"15ｷ" just before every term.
13 - 2/5 = H + 6 - 4/15
15ｷ13 - 15ｷ2/5 = 15ｷH + 15ｷ6 - 15ｷ4/15
Now we multiply
15ｷ13 and get 195
-15ｷ2/5 and get -6
15ｷH and get 15H
15ｷ6 and get 89
-15ｷ4/15 and get -4
So the equation is now
195 - 6 = 15H + 90 - 4
Combine the 195 and -6 on the left and get 189
Combine 90 and -4 on the right and get 86
189 = 15H + 86
Add -86 to both sides to get rid of the 86 on the
right, leaving only a term in H
189 = 15H + 86
-86 -86
覧覧覧覧覧覧覧覧覧
103 = 15H
Now th get rid if the 15 coefficient, we divide
both terms by 15:
103/15 = 15H/15
103/15 = H
That's the solution, 103/15, which you can write
as 6 13/15. However in algebra, improper fractions
are quite proper!!! :-)
Edwin
