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-1 + 41log3(-3x) = 7
Isolate the log term by adding 1
to both sides:
41log3(-3x) = 8
Divide both sides by 41
log3(-3x) = 8/41
Use this rule of logarithms:
The logarithm equation logBA = C can be
rewritten equivalently as the exponential
equation A = BC
-3x = 38/41
Divide both sides by -3
x = (38/41) ÷ (-3)
x = -(38/41)÷(31)
Subtract exponents of 3:
x = -38/41-1
x = -38/41-41/41
x = -3-33/41
x = -1/(333/41)
x = -.413024273, approximately
Edwin
