SOLUTION: Find the value of k so that the line through the given points has slope m. 48) (1,k),(5, absolute value of k); m = 3

Algebra ->  Linear-equations -> SOLUTION: Find the value of k so that the line through the given points has slope m. 48) (1,k),(5, absolute value of k); m = 3      Log On


   

Question 648496: Find the value of k so that the line through the given points has slope m.
48) (1,k),(5, absolute value of k); m = 3
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

slope is rise over run, meaning the differences of y over the differences of x

If you have (1,k) and (5, |+k|), then the difference of the y-coordinates is
(|k|-k)/(5-1)...so it could be %28k-k%29%2F%285-1%29=0, or
+%28-k-k%29=-2k%2F4=-k%2F2, and
the difference of the x-coordinates is 5-1=4

so, m=-k%2F2
if m=3, then 3=-k%2F2....->...3%2A2=-k->...6=-k..->...-6=k
and, your points will be
(1,-6),(5, 6); m=3
check equation:
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (1, -6) and (x2, y2) = (5, 6).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%286--6%29%2F%285-1%29+=+3.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 3%2A1+%2Bb+=+-9. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-6-3%2A1+=+-9.

y=(3)x + (-9)

Your graph: