SOLUTION: Please tell me if I am on the right track. I am to sketch the graph and id the foci of: 9(x-1)^2+4(y+3)^2=36. I came up with foci (1,-3+sqrt5) and (1,-3-sqrt5). Which is (1,-.764)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please tell me if I am on the right track. I am to sketch the graph and id the foci of: 9(x-1)^2+4(y+3)^2=36. I came up with foci (1,-3+sqrt5) and (1,-3-sqrt5). Which is (1,-.764)       Log On


   

Question 64838: Please tell me if I am on the right track. I am to sketch the graph and id the foci of: 9(x-1)^2+4(y+3)^2=36. I came up with foci (1,-3+sqrt5) and (1,-3-sqrt5). Which is (1,-.764) and (1,-5.236).
Then I am to find the center of x^2+y^2=12x-12y. I came up with the center at (6,-6)with radius sqrt72. How did I do?
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
You did great. The only thing I would do is simplify sqrt%2872%29
sqrt%2836%29%2Asqrt%282%29=6%2Asqrt%282%29
Happy Calculating, keep up the good work!!!!