SOLUTION: Could you show your work, step by step, on how this expression 15x^2-16xy+4y^2 would be factorized. I have no idea how to do this.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Could you show your work, step by step, on how this expression 15x^2-16xy+4y^2 would be factorized. I have no idea how to do this.      Log On


   



Question 648155: Could you show your work, step by step, on how this expression 15x^2-16xy+4y^2 would be factorized. I have no idea how to do this.
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Could you show your work, step by step, on how this expression 15x^2-16xy+4y^2 would be factorized.
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I think you problem should be 16x^2-16xy+4y^2
which factors as (4x-2y)^2
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Check to see if you possibly have a typo on your problem source.
Cheers,
Stan H.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression 15x%5E2-16xy%2B4y%5E2, we can see that the first coefficient is 15, the second coefficient is -16, and the last coefficient is 4.


Now multiply the first coefficient 15 by the last coefficient 4 to get %2815%29%284%29=60.


Now the question is: what two whole numbers multiply to 60 (the previous product) and add to the second coefficient -16?


To find these two numbers, we need to list all of the factors of 60 (the previous product).


Factors of 60:
1,2,3,4,5,6,10,12,15,20,30,60
-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 60.
1*60 = 60
2*30 = 60
3*20 = 60
4*15 = 60
5*12 = 60
6*10 = 60
(-1)*(-60) = 60
(-2)*(-30) = 60
(-3)*(-20) = 60
(-4)*(-15) = 60
(-5)*(-12) = 60
(-6)*(-10) = 60

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -16:


First NumberSecond NumberSum
1601+60=61
2302+30=32
3203+20=23
4154+15=19
5125+12=17
6106+10=16
-1-60-1+(-60)=-61
-2-30-2+(-30)=-32
-3-20-3+(-20)=-23
-4-15-4+(-15)=-19
-5-12-5+(-12)=-17
-6-10-6+(-10)=-16



From the table, we can see that the two numbers -6 and -10 add to -16 (the middle coefficient).


So the two numbers -6 and -10 both multiply to 60 and add to -16


Now replace the middle term -16xy with -6xy-10xy. Remember, -6 and -10 add to -16. So this shows us that -6xy-10xy=-16xy.


15x%5E2%2Bhighlight%28-6xy-10xy%29%2B4y%5E2 Replace the second term -16xy with -6xy-10xy.


%2815x%5E2-6xy%29%2B%28-10xy%2B4y%5E2%29 Group the terms into two pairs.


3x%285x-2y%29%2B%28-10xy%2B4y%5E2%29 Factor out the GCF 3x from the first group.


3x%285x-2y%29-2y%285x-2y%29 Factor out -2y from the second group.


%283x-2y%29%285x-2y%29 Factor out 5x-2y


So the final answer is %283x-2y%29%285x-2y%29


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