SOLUTION: 4x squared-4x-99=0

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Question 648116: 4x squared-4x-99=0
Found 2 solutions by stanbon, Algebraic:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
4x squared-4x-99=0
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4x^2 - 4x - 99 = 0
Factor:
(2x-11)(2x+9) = 0
x = 11/2 or x = -9/2
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Cheers,
Stan H.
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Answer by Algebraic(50) About Me  (Show Source):
You can put this solution on YOUR website!
Original problem: 4x%5E2-4x-99
We're going to be factoring this to extract the roots (what 'x' equals)
Step 1: We must find two numbers that when '4' and '-99' multiply, will divide to give you '-4' in the middle.
4x%5E2-4x-99
You have quite a few number of combinations:
The 4x%5E2 can be broken up into
%284x++%29%28x++%29
or
%282x++%29%282x++%29
We know that '-99' has six factors, and these include:
1 x 99, 3 x 33, and 9 x 11
Step 2: Let's start trying to see what will work and not work (trial and error method)
We know that regardless of signs, none of the factors of '-99' will be able to multiply here to give you a '-4' in the middle using this equation:
%284x+%2B+3+%29%28x+-+33+%29 ---> Does not work, gives you -33x+%2B+3x in the middle
%284x+-+3+%29%28x+%2B+33+%29 ---> Does not work, gives you 33x+-+3x in the middle
%284x+%2B++1+%29%28x+-+99+%29 ---> Does not work, gives you -396x+%2B+x in the middle
%284x+-+1+%29%28x+%2B+99+%29 ---> Does not work, gives you 396x+-+x in the middle
%284x+%2B+9+%29%28x+-+11+%29 ---> Does not work, gives you -44x+%2B+9x in the middle
%284x+-+9+%29%28x+%2B+11+%29 ---> Does not work, gives you 44x+-+9x in the middle
Now that we know that the %284x++%29%28x++%29 equation won't work, let's move on to the other equation that could possibly work..
Step 3: Let's start trying to see what will work and not work (trial and error method)
We know that '-99' has six factors, and these include:
1 x 99, 3 x 33, and 9 x 11
We know that regardless of signs, none of the factors of '-99' will be able to multiply here to give you a '-4' in the middle using this equation:
%282x+%2B+1+%29%282x+-+99+%29 ---> Does not work, gives you -198x+%2B+2x in the middle
%282x+-+1+%29%282x+%2B+99+%29 ---> Does not work, gives you 198x+-+2x in the middle
%282x+%2B+3+%29%282x+-+33+%29 ---> Does not work, gives you -66x+%2B+6x in the middle
%282x+-+3+%29%282x+%2B+33+%29 ---> Does not work, gives you 66x+-+6x in the middle
%282x+%2B+9+%29%282x+-+11+%29 ---> Works!! Gives you -22x+%2B+18x in the middle, which is equivalent to '-4x'
%282x+-+9+%29%282x+%2B+11+%29 ---> Does not work, gives you 22x+-+18x in the middle
So.. now we know that the factored version of the equation you provided is:
%282x+%2B+9+%29%282x+-+11+%29
To get the roots, you must set each parenthesis equal to zero like so..
Step 1: Set each parenthesis equal to zero
%282x+%2B+9+%29=0
%282x+-+11+%29=0
Step 2: Let's solve each one at a time
%282x+%2B+9+%29=0
Subtract '9' from both sides to get the '2x' by itself
%282x+%2B+9+%29=0
2x=-9
Divide both sides by '2' to get 'x' by itself
2x=-9
x=%28-9%2F2%29
First root is x=%28-9%2F2%29
Step 3: Let's find the other root
%282x+-+11+%29=0
Add '11' to both sides to get the '2x' by itself
%282x+-+11+%29=0
2x=11
Divide both sides by '2' to get the 'x' by itself
2x=11
x=%2811%2F2%29
Second root is x=%2811%2F2%29
So, the factored version of this equation is %282x+%2B+9+%29%282x+-+11+%29 and its roots are x=%28-9%2F2%29 and x=%2811%2F2%29