SOLUTION: how do you solve this system of equations: 2x-3y+z=5 x+3y+8z=22 3x-y+2z=12

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Question 647926: how do you solve this system of equations:
2x-3y+z=5
x+3y+8z=22
3x-y+2z=12
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The system
2x-3y+z=5
x+3y+8z=22
3x-y+2z=12

converts to the matrix



Now row reduce to get
(Solution provided by the Linear Algebra Toolkit)

(Solution provided by the Linear Algebra Toolkit)

So the solutions are

x+=+3, y+=+1, and z+=+2