Question 64761: Given a line containing the points (1,3), (2,4), (3,5) determine the slope-intercept form of the equation, give one additional point on this line and graph the function.
What is the equation of line in slope-intercept form?
Give one additional point in (x,y) form that would fall on this line:
Graph the function:
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! FIRST FIND THE SLOPE
(4-3)/(2-1)
1/1=1 SLOPE IS 1
NOW SUBSTITUTE ONE SET OF POINTS IN THE EQUATION Y=mX+b TO FIND THE Y INTERCEPT
3=1+b
b=3-1
b=2 THUS WE HAVE THE LINE EQUATION
AN ADDITIONAL POINT ON THIS LINE CAN BE FOUND BY SETTING Y=0 THUS
0=X+2
X=-2 OR THE OTHER POINT IS(-2,0)
(graph 300x200 pixels,x from -6 to 6,y from -6 to 6, y+x+2)
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