SOLUTION: Your question: Professor I'm having trouble with solving absolute value equations and inequalities. Hopefully this is clear. /z+8/>0 (A) - infinity, infinity (B) 0 (C) -8, infi

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Question 647544: Your question:
Professor I'm having trouble with solving absolute value equations and inequalities. Hopefully this is clear. /z+8/>0
(A) - infinity, infinity (B) 0 (C) -8, infinity. Or (D) -8,8 thank you

Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
abs%28z%2B8%29+%3E+0
z%2B8+%3E0
and
-%28z%2B8%29+%3E+0 = z%2B8+%3C+0
z+%3E+-8 and z%3C-8
This means it can be ANY value but -8 since -8 makes us have 0.
In interval notation: (-inf,-8) U (-8,inf)
I do not see this answer, but this is the answer.
If this was supposed to be abs%28z%2B8%29+%3E=+0 then the answer would be A, since -8 would no longer be a problem.