SOLUTION: The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What is the probability that the height of an 18-year-old
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Question 647523: The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What is the probability that the height of an 18-year-old man selected at random is between 64 inches and 66 inches.
a. .1597
b. .2017
c. .3677
d. .8403
e. .3403
If possible please show me how the problem is solved so maybe I can figure out as well Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What is the probability that the height of an 18-year-old man selected at random is between 64 inches and 66 inches.
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When you need to measure propability or percentage, you need to use
the z-scale.
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z(64) = (64-68)/3 = -1.3333
z(66) = (66-68)/3 = -0.6667
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P(64 <= x <= 66) = P(-1.33 <= z <= -0.67)
= normalcdf(-1.3333,-0.6667) = 0.1613
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Cheers,
Stan H.
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a. .1597
b. .2017
c. .3677
d. .8403
e. .3403
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