SOLUTION: Solve for x log(xy) + log(x2y5) = 21

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Question 647479: Solve for x
log(xy) + log(x2y5) = 21
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
We'll use properties: log(ab) = log(a) + log(b); log(x^a) = alog(x)
log(xy) + log(x^2y^5) = 21}}}
log(x) + log(y) + log(x^2) + log(y^5) = 21}}}
log(x) + log(x^2) + log(y^6) = 21}}}
log(x*x^2) = 21 - log(y^6)
log(x^3) = 21 - 6log(y)
3*log(x) = 21 - 6log(y)
log(x) = (21-6log(y))/3
10^log(x) = 10^((21-6log(y))/3)
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x = 10^(%2821-6log%28y%29%29%2F%283%29)