SOLUTION: Hey, I've tried this problem a few times. I think I may have gotten it when I added the 0x's. Please let me know what I'm doing wrong. It's long division. This is on the outside:

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Question 647391: Hey, I've tried this problem a few times. I think I may have gotten it when I added the 0x's. Please let me know what I'm doing wrong.
It's long division.
This is on the outside:

this is on the inside:

This is how I worked it:
Outside:

Inside:

My answer:

When I preview it my answer shows only 65 divided by x^2 but it is 12x - 65 over x^2 +4.
The question is in there right though!
Thank you!
Carrie
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi,
3x^2 + x -12
x^2+4 | 3x^4 - 2x^3 + x^3 + 4x -33
- (3x^4 + 12x^2 )
x^3 - 12x^2 + 4x
-( x^3 +4x )
-12x^2 -33
-(-12 x^2 -48)
15

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
It's long division.
This is on the outside:

this is on the inside:

This is how I worked it:
Outside:

Inside:

---------
Dividing by x^2 + 4 you get 3x^2
Multiplying 3x^2(x^2+4) you get 3x^4+12x^2 which you place in appropriate columns
----
Sutractiing you get x^3-12x^2 + 4x - 33
--------
Dividing by x^2 + 4 you get x
Multiplying x(x^2+4) you get x^3+4x
-------
Subtracting you get -12x^2 - 33
--------
Dividing by x^2+4 you get -12
Multiplying -12(x^2+4) you get -12x^2-48
--------
Subtracting you get +15
That is the Remainder.
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Cheers,
Stan H.
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