SOLUTION: {{{ 2x^2-x+2xy=3 }}} {{{ 3xy+3x^2-y=5 }}}

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: {{{ 2x^2-x+2xy=3 }}} {{{ 3xy+3x^2-y=5 }}}       Log On


   

Question 647373: +2x%5E2-x%2B2xy=3+
+3xy%2B3x%5E2-y=5+
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for y in the 2nd equation:
3xy+%2B+3x%5E2+-+y+=+5 -> y%283x-1%29+=+5+-+3x%5E2
y+=+%285-3x%5E2%29%2F%283x-1%29
Substitute in the 1st:
2x%5E2+-+x+%2B+2x%28%285-3x%5E2%29%2F%283x-1%29%29+=+3
Simplifying the above expression gives
5x%5E2+-+2x+-+3+=+0
This can be factored as
%285x%2B3%29%28x-1%29+=+0
The solutions are x = -3/5, x = 1
If x=1, y+=+%285-3%29%2F%283-1%29+=+1
If x=-3/5, y+=+%285-3%28-3%2F5%29%5E2%29%2F%283%28-3%2F5%29-1%29+=+-1+2%2F5