SOLUTION: the perimeter of a rectangle is 52 feet ans its width is 6 less then is lenght. Find the length and width of the rectangle.

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Question 64722: the perimeter of a rectangle is 52 feet ans its width is 6 less then is lenght. Find the length and width of the rectangle.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
W=L-6 THEN
2*L+2(L-6)=52
2L+2L-12=52
4L=64
L=64/4
L=16 SOLUTION FOR THE LENGTH THEN
W=16-6
W=10 SOLUTION
PROOF
2*16=2*10=52
32+20=52
52=52