SOLUTION: A dead mans hand is aka a pair 8's and a pair of aces, what is the probality of being dealt the dead man's hand(any two aces any two 8's and one other card that is not an ace or an

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Question 64706This question is from textbook Asurvey of Mathematics
: A dead mans hand is aka a pair 8's and a pair of aces, what is the probality of being dealt the dead man's hand(any two aces any two 8's and one other card that is not an ace or an eight) when five cards are dealt. This question is from textbook Asurvey of Mathematics

Answer by stanbon(75887) (Show Source):
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A dead mans hand is aka a pair 8's and a pair of aces, what is the probality of being dealt the dead man's hand(any two aces any two 8's and one other card that is not an ace or an eight) when five cards are dealt.
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Draw a pair of 8's: 4C2=6 ways
Draw a pair of ace's: 4C2=6 ways
Draw a card not ace or 8: 48C1=48 ways
# of ways to get the cards you need: 6*6*48=1728
#of ways to get any hand of 5 cards: 52C5=2598960
Prob(dead man's hand)= 1728/2598960=0.00066488... or 0.06%
Cheers,
Stan H.