SOLUTION: We are in interval notation and I am havibg a hard time with. Could you please help? We are to use interval notaion for the solution sets. 2<(5-2x)<7 Here is another one

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: We are in interval notation and I am havibg a hard time with. Could you please help? We are to use interval notaion for the solution sets. 2<(5-2x)<7 Here is another one       Log On


   

Question 64683: We are in interval notation and I am havibg a hard time with. Could you please help?
We are to use interval notaion for the solution sets.
2<(5-2x)<7
Here is another one 2x-3<5 or 3x-2>13
Thanks
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
We are to use interval notaion for the solution sets.
2<(5-2x)<7
Subtract 5 along the line to get:
-3<-2x<2
Divide thru by -2 to get:
This reverses the inequality.
-1 In interval notation: (-1,3/2)
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Here is another one 2x-3<5 or 3x-2>13
2x<8 or 3x>15
x<4 or x>5
(-inf,4)U(5,inf)
Or you could write it as:
(-inf,4) or (5,inf)
Cheers,
Stan H.