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Question 64677This question is from textbook An Incremental Development
: Jonathan has 136 coins in this collection of dimes and quarters. If the coins have a total of $28, how many are dimes and how many are quarters?
This question is from textbook An Incremental Development
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! Let x=number of quarters
then 136-x=number of dimes
To make life easier for me, I choose to deal in pennies.
25x is the amount of money in quarters.
10(136-x) is the amount of money in dimes.
Now we are told that the amount of money in quarters (25x) plus the amount of money in dimes 10(136-x) equals $28 or 2800 pennies. Thus, our equation to solve is:
25x+10(136-x)=2800 simplifying we get:
25x+1360-10x=2800 collecting like terms, we have:
25x-10x=2800-1360
15x=1440
x=96 quarters
136-96=40 dimes
ck
10(40)+96(25)=2800
400+2400=2800
2800=2800
Hope this helps. Happy holidays.----ptaylor
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