SOLUTION: How to do these?? 1 : q - 3 r = 2 for r 2: 3g+7= 11g-17 3: -8+4y=Y- 6+3y- 2 4: 7+3d- S=-1+2d- 12+d 5: 2fgh-3g= 10 forh Thanks In advance

Algebra ->  Absolute-value -> SOLUTION: How to do these?? 1 : q - 3 r = 2 for r 2: 3g+7= 11g-17 3: -8+4y=Y- 6+3y- 2 4: 7+3d- S=-1+2d- 12+d 5: 2fgh-3g= 10 forh Thanks In advance      Log On


   

Question 646700: How to do these??
1 : q - 3 r = 2 for r
2: 3g+7= 11g-17
3: -8+4y=Y- 6+3y- 2
4: 7+3d- S=-1+2d- 12+d
5: 2fgh-3g= 10 forh
Thanks In advance
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

1 :
q+-+3+r+=+2..... for r
q+-+2+=+3+r
%28q+-+2%29%2F3+=++r

2:
3g%2B7=+11g-17
17%2B7=+11g-3g
24=+8g
24%2F8=+g
3=+g


3:
-8%2B4y=y-6%2B3y-2
-8%2B4y=-6%2B4y-2
cross%28-8%29%2Bcross%284y%29=cross%28-8%29%2Bcross%284y%29
0=0.......equation is true; -8%2B4y is equal to y-6%2B3y-2
4:
7%2B3d-S=-1%2B2d-12%2Bd...I guess you need to solve for d
7%2B3d-2d-d=-13%2BS
7%2Bcross%283d%29-cross%283d%29%2B13=S
20=S

5:
2fgh-3g=+10...... for h
2fgh=+10%2B3g
h=+%2810%2B3g%29%2F2fg
h=+10%2F2fg%2B3g%2F2fg
h=+cross%2810%295%2Fcross%282%29fg%2B3cross%28g%29%2F2fcross%28g%29
h=+5%2Ffg%2B3%2F2f