Question 646433: whats the axis of symmetry, the x-intecept, the y-intercept, the vertex, the range,and the domain for: f(x)= -x^2-10x-26
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! whats the axis of symmetry, the x-intecept, the y-intercept, the vertex, the range,and the domain for: f(x)= -x^2-10x-26
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f(x)= -x^2-10x-26
complete the square
f(x)= -(x^2+10x+25)+25-26
f(x)=-(x+5)^2-1
This is an equation of a parabola that opens downwards with vertex at (-5,-1)
axis of symmetry: x=-5
..
y-intercept
set x=0
y=-26
..
x-intercept
set y=0
-(x+5)^2-1=0
(x+5)^2=-1
x+5=±√-1
x=-5±√-1
no real roots
x-intercept:none
..
Range: (-1,∞)
Domain: (-∞,∞)
See graph below:
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