SOLUTION: solve and graph x^2-10x+24>0

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Question 646233: solve and graph x^2-10x+24>0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

 y = x^2-10x+24    ||Completing Square to put Parabolic function in Vertex form

 y = (x-5)^2 - 25 + 24

 y = (x-5)^2 - 1  V(5,-1)

Graph y = (x-5)^2 - 1  and determine where the function is > 0

{x | x < 4  or x > 6}