SOLUTION: I want to be shown the math to this problem and how to get the answer. When the smaller of 2 consecutive integers is added to four times the larger, the result is 59. What are t

Smaller consecutive integer = N
Larger consecutive integer = N+1
Four times the larger = 4(N+1)

We read this:

So we stick a + sign between them like this:

    Four times the larger + Smaller consecutive integer

or
                        N + 4(N+1)
Then we read this:

So we stick an = and a 59 after that:

                        N + 4(N+1) = 59

Solve that and get N = 11, so

Smaller consecutive integer = N = 11
Larger consecutive integer = N+1 = 11+1 = 12
Four times the larger = 4(N+1) = 4(11+1) = 4(12) = 48

Checking: When 11 is added to 48, the result is indeed 59.

Edwin