Question 646075: A and B are two-digit numbers. Find the sum of the digits of the largest value for A such that A:B=4:7
Found 2 solutions by Edwin McCravy, MathTherapy:
Answer by Edwin McCravy(20065)   (Show Source):
You can put this solution on YOUR website!
To be in the ratio 4:7, the smaller 2-digit number
must be an integer times 4 and the larger 2-digit number
must be that same integer times 7.
The largest 2-digit multiple of 7 is 12×7 = 98. That's B.
So the smaller one, A, must be 12×4 or 48, and that's as
large as A can be.
So A = 48 and B = 98
The sum of the digits of 48 is 4+8 = 12.
Edwin
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website! A and B are two-digit numbers. Find the sum of the digits of the largest value for A such that A:B=4:7
The largest 2-digit multiple of 7, the larger of the 2 ratios, is 98 (7 * 14)
Therefore, multiplying 4 by 14 to keep the 4:7 ratio gives us 56
The new ratio is now: 56:98
Therefore, the largest value for A = 56, and the sum of its digits = 5 + 6, or 
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