SOLUTION: Could you show me how to simplify the expression 2^(x+1)=6^(x-1) using logarithmic principles

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Question 645972: Could you show me how to simplify the expression 2^(x+1)=6^(x-1) using logarithmic principles
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
2^(x+1) = 6^(x-1)
log%282%5E%28x%2B1%29%29+=+log%286%5E%28x-1%29%29
:
using the log equiv of exponents
(x+1)*log(2) = (x-1)*log(6)
:
Find the logs of 2 and 6; then just basic algebra
.301(x+1) = .778(x-1)
.301x + .301 = .778x - .778
.301 + .778 = .778x - .301x
1.079 = .477x
x = 1.079/.477
x = 2.262
:
:
You can confirm this on your calc,
enter 2^(2.262+1) results: 9.593
enter 6^(2.261-1) results: 9.594 (logs are not exact)