SOLUTION: A radioactive material decays according to the law: f(t)=500e^-0.47t where f(0) is the initial amount present in grams and f(t) is the amount present at time t (hours). Determine h

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: A radioactive material decays according to the law: f(t)=500e^-0.47t where f(0) is the initial amount present in grams and f(t) is the amount present at time t (hours). Determine h      Log On


   



Question 64591: A radioactive material decays according to the law: f(t)=500e^-0.47t where f(0) is the initial amount present in grams and f(t) is the amount present at time t (hours). Determine how many hours it will take for the material to decay to 100 grams using either graphic or algebraic methods.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A radioactive material decays according to the law: f(t)=500e^-0.47t where f(0) is the initial amount present in grams and f(t) is the amount present at time t (hours). Determine how many hours it will take for the material to decay to 100 grams using either graphic or algebraic methods
:
500*e^-.47t = 100
:
Step by step, find t:
:
Divide both sides by 500
e^-.47t = 100/500
e^-.47t = .2
:
Find the nat log of both sides:
ln(e^-.47t) = ln(.2)
:
log equiv of exponents:
-.47t*ln(e) = ln(.2)
:
Find the nat log of .2; Remember the natural log of e is 1
-.47t*1 = -1.6093438
:
Divide both sides by -.47
t = -1.6093438/-.47
t = +3.424 hrs
:
:
Check on a good calc like a Ti83; key in: 500*(e^(-.47*3.424)) = 100.01 ~ 100
:
did this help?