You can put this solution on YOUR website! form a polynomial with real co-efficents given degrees and zeros.
degree 5 zeros -5,-1,6+i
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Since the coefficients are Real Numbers the zeroes are:
-5, i, -i, 6+i, 6-i
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Equation:
f(x) = (x+5)(x-i)(x+i)(x-(6+i))(x-(6-i))
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f(x) = (x+5)(x^2+1)((x+6)^2+1)
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f(x) = (x+5)(x^2+1)(x^2+12x+37)
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Cheers,
Stan H.
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