You can put this solution on YOUR website! Compute the exact value of tan{tan^-1{1/5}+ tan^-1{2/3}}
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Form: tan(a+b)=[tan(a) + tan(b)]/[1-(tan(a)*tan(b)]
Your a=arctan(1/5)
Your b=arctan(2/3)
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tan{tan^-1{1/5}+ tan^-1{2/3}}=[1/5+2/3]/[1-(1/5)(2/3)]
=[13/15]/[1-2/15]
=[13/15]/[13/15]
=1
Cheers,
Stan H.