SOLUTION: How many gallons of 20% alcohol solution must be mixed with 10 gallons of a 50% alcohol solution to obtain a 30% alcohol solution?

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Question 645445: How many gallons of 20% alcohol solution must be mixed with 10 gallons of a 50% alcohol solution to obtain a 30% alcohol solution?
Answer by sachi(548) About Me  (Show Source):
You can put this solution on YOUR website!
let x gl of 20% alcohol solution must be mixed with 10 gallons of a 50% alcohol solution to obtain a 30% alcohol solution
so 20x/100+10*50/100=(x+10)*30/100
or 20x+500=30(x+10)=30x+300
or 10x=200
or x=20 gallons
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