SOLUTION: 1+(m+1)^3=?

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Question 644989: 1+(m+1)^3=?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
1%2B%28m%2B1%29%5E3=0
1%2B%28m%2B1%29%28m%2B1%29%28m%2B1%29=0
1%2B%28m%5E2%2Bm%2Bm%2B1%29%28m%2B1%29=0
1%2B%28m%5E2%2B2m%2B1%29%28m%2B1%29=0
1%2Bm%5E3%2Bm%5E2%2B2m%5E2%2B2m%2Bm%2B1=0
m%5E3%2B2m%5E2%2Bm%5E2%2B2m%2Bm%2B2=0
m%5E2%28m%2B2%29%2Bm%28m%2B2%29%2B%28m%2B2%29=0
%28m%2B2%29%28m%5E2%2Bm%2B1%29=0
zeros:
if m%2B2=0......=>...m=-2.......real root

if %28m%5E2%2Bm%2B1%29......=>...use quadratic formula to find zeros

m+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
m+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29+
m+=+%28-1+%2B-+sqrt%28+1-4+%29%29%2F2+
m+=+%28-1+%2B-+sqrt%28+-3+%29%29%2F2+
m+=+%28-1+%2B-+i%28sqrt%28+3+%29%29%29%2F2+
roots:
m+=+-1%2F2+%2B+i%28sqrt%28+3+%29%29%2F2+
m+=+-1%2F2+-+i%28sqrt%28+3+%29%29%2F2+........complex roots
+graph%28+600%2C+600%2C+-5%2C+5%2C+-5%2C+5%2C+1%2B%28x%2B1%29%5E3%29+