SOLUTION: I need help finding the zeros of: F(x)= 4x^3-24x^2-x+6=0

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Question 644892: I need help finding the zeros of:
F(x)= 4x^3-24x^2-x+6=0
Found 2 solutions by MathLover1, stanbon:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
F%28x%29=+4x%5E3-24x%5E2-x%2B6=0
4x%5E3-x-24x%5E2%2B6=0...group
%284x%5E3-x%29-%2824x%5E2-6%29=0
x%284x%5E2-1%29-6%284x%5E2-1%29=0
%28x-6%29%284x%5E2-1%29=0
%28x-6%29%282x-1%29%282x%2B1%29=0
solutions:
if x-6=0........=>..x=6
if 2x-1=0........=>..2x=1=>..x=1%2F2
if 2x%2B1=0........=>..2x=-1=>..x=-1%2F2

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+4x%5E3-x-24x%5E2%2B6%29+




Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
help finding the zeros of:
F(x)= 4x^3-24x^2-x+6=0
-----
Factor: 4x^2(x-6)-(x-6) = 0
(x-6)(4x^2-1) = 0
x = 6 or x = 1/2 or x = -1/2
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Cheers,
Stan H.