SOLUTION: THE SIZE OF EACH INTERIOR ANGLE OF A REGULAR POLYGON IS 11 TIMES THE SIZE OF EACH EXTERIOR ANGLE. WORK OUT THE NUMBER OF SIDES THE POLYGON HAS.

Algebra ->  Polygons -> SOLUTION: THE SIZE OF EACH INTERIOR ANGLE OF A REGULAR POLYGON IS 11 TIMES THE SIZE OF EACH EXTERIOR ANGLE. WORK OUT THE NUMBER OF SIDES THE POLYGON HAS.      Log On


   



Question 644886: THE SIZE OF EACH INTERIOR ANGLE OF A REGULAR POLYGON IS 11 TIMES THE SIZE OF EACH EXTERIOR ANGLE.
WORK OUT THE NUMBER OF SIDES THE POLYGON HAS.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
THE SIZE OF EACH INTERIOR ANGLE OF A REGULAR POLYGON IS 11 TIMES THE SIZE OF EACH EXTERIOR ANGLE.
WORK OUT THE NUMBER OF SIDES THE POLYGON HAS.
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Equation:
x + 11x = 180
12x = 180
x = 15 degrees (size ofr each exterior angle)
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Fact: Sum of all the exterior angles is 360 degrees
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# of sides = # of exterior angles = 360/15 = 24
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Cheers,
Stan H.
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