SOLUTION: I am having troubles solving this algebraically, must give exact solutions, the equation is: 2cos^2x + 3cosx +1 =0
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Question 644729: I am having troubles solving this algebraically, must give exact solutions, the equation is: 2cos^2x + 3cosx +1 =0 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! For [0,π], solve for x
2cos^2x + 3cosx +1 =0
(2cosx+1)(cosx+1)=0
2cosx+1=0
cosx=-1/2
x=2π/3
or
cosx+1
cosx=-1
x=π
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