SOLUTION: Two sides of a triangle have the same lengths. The third side measures 2m less than the common length. The perimeter is 22m. What I tried: 2x+2(x-2)=22 2x+2-4=22 4x = 26 x=

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Question 644581: Two sides of a triangle have the same lengths. The third side measures 2m less than the common length. The perimeter is 22m.
What I tried:
2x+2(x-2)=22
2x+2-4=22
4x = 26
x= 6.5
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Let x = length of common length

so we have 2 sides of length x and a third side of length x - 2 (since "The third side measures 2m less than the common length")

Add them all up and set that equal to the perimeter 22. Then solve.

x+x + x-2 = 22

3x-2 = 22

3x = 22+2

3x = 24

x = 24/3

x = 8

So the 2 equal sides are 8 meters. The third unequal side is 8-2 = 6 meters.

Check:

Side1 + Side2 + Side3 = Perimeter

S1 + S2 + S3 = P

8+8+6 = 22

22 = 22

Answer checks out

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Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Two sides of a triangle have the same lengths. The third side measures 2m less than the common length. The perimeter is 22m.
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1st, what is your question?
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What I tried:
2x+2(x-2)=22
2x+2-4=22
4x = 26
x= 6.5
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If you want to find the sides:
2 sides are x, the 3rd is x-2
2x + x-2 = 22
3x = 24
x = 8
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What is your question?