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| Question 64443This question is from textbook algebra II
 :  This looks very vexing to me because I dont' understand it. Help!
 Graph f(x) 3x^2-6x-1.  plot at least 5 points.
 Of those 5 points, state the vertex point, whether the vertex point is maximum or minimum and the equation of axis of symmetry. 
This question is from textbook algebra II
 
 Found 2 solutions by  Earlsdon, stanbon:
 Answer by Earlsdon(6294)
      (Show Source): 
You can put this solution on YOUR website! Graph:  Here's the graph:
 
  The equation of the line of symmetry is given by:
 
  The a and the b come from the general form of the quadratic equation:  In your equation, a = 3 and b = -6, so:
 
  
  is the equation of the line of symmetry. Since the line of symmetry passes thrugh the vertex, you can find the coordinates of the vertex by substituting x = 1 into the quadratic equation and solving for y.
 
  Substitute x=1 and solve for y. 
  Simplify. 
  The vertex point is at (1, -4) Confirm this on the graph.
 The graph shows that the vertex point is a minimum.
 To find four more points to meet your requirement, simply choose four conveniently small values of x and substitute these, one-by-one into the quadratic equation and solve for four values of y.
 Let x = 0 for point1.
 
  
   Point1 is (0, -1)
 Let x = 1 for point2. You've got this one already, it's the vertex point (1, -4)
 Let x = 2 for point3.
 
  
  
  Point3 is (2, -1)
 I hesitate to deprive you of the pleasure of doing your own math so perhaps you can finish this yourself.
 
Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Graph f(x)= 3x^2-6x-1. plot at least 5 points. Of those 5 points, state the vertex point, whether the vertex point is maximum or minimum and the equation of axis of symmetry.
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 If x=0 y=-1
 If x=1 y=3-6-1=-4
 If x=-1 y=3+6-1=8
 If x=2 y==12-12-1=-1
 If x=-2 y=12+12-1=23
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 Complete the square to find the vertex and axis of symmetry:
 3x^2-6x=y+1
 3(x^2-2x)=y+1
 x^2-2x=(1/3)(y+1)
 Complete the square:
 x^2-2x+1=(1/3)(y+1)+1
 (x-1)^2=(1/3)(y+1+3)
 (x-1)^2=(1/3)(y+4)
 So, Vertex = (1,-4) is a minimum point because the parabola opens up.
 Axis of symmetry is x=1
 
  Cheers,
 Stan H.
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