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Question 644385: What are the zeros of the function f(x) = x^3-x^2-25x+25?
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! f(x) = x^3-x^2-25x+25
0 = x^3-x^2-25x+25
x^3-x^2-25x+25 = 0
(x^3-x^2)+(-25x+25) = 0
x^2(x-1)+(-25x+25) = 0
x^2(x-1)-25(x-1) = 0
(x^2-25)(x-1) = 0
(x-5)(x+5)(x-1) = 0
x-5 = 0, x+5 = 0 or x-1 = 0
x = 5, x = -5 or x = 1
So the zeros are x = 5, x = -5 or x = 1
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