SOLUTION: How do you find the x and y intercept of points (-6,-2) and (-1,3). This is the only one i can't figure out but I got the slope as 5/7. thanks!

Algebra ->  Coordinate-system -> SOLUTION: How do you find the x and y intercept of points (-6,-2) and (-1,3). This is the only one i can't figure out but I got the slope as 5/7. thanks!      Log On


   

Question 644336: How do you find the x and y intercept of points (-6,-2) and (-1,3). This is the only one i can't figure out but I got the slope as 5/7. thanks!
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
The slope is NOT 5/7 its 1 because %283+-+%28-2%29%29%2F%28-1-%28-6%29%29+=+1.
The equation of the line is
y+%2B+2+=+x+%2B+6 or
x+-+y+=+-4
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 1+x+%2B+-1+y+=+-4 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-1%2F-1.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -4/1 = -4.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -4/-1 = 4.
  • Slope is -1/-1 = 1.
  • Equation in slope-intercept form: y=1*x+4.
graph%28+500%2C+500%2C+-4-8%2C+-4%2B8%2C+4-8%2C+4%2B8%2C+1%2Ax%2B4+%29+