Question 644183: How many liters of a 20% alcohol solution must be mixed with 30 liters of a 90% solution to get a 80% solution? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! How many liters of a 20% alcohol solution must be mixed with 30 liters of a 90% solution to get a 80% solution?
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30*90 + x*20 = (x+30)*80