You can put this solution on YOUR website! if a car is traveling at 60 mph and a truck leaves the same location 15 mins later and travels at 74mph when will they meet?
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Early-car DATA:
rate = 60 mph ; time = x hrs ; distance = 60x miles
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Later-car DATA:
rate = 74 mph ; time = x-(1/4) hrs ; distance = 74(x-(1/4)) = (74x - 18.5) miles
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Equation:
60x = 74x-18.5
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14x = 18.5
x = 1.32 hrs or 1 hr 19.28 minutes
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Cheers,
Stan H.
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