SOLUTION: I have done 7/10 of my homework. I will submit each one separately. The answers are randomized on the back, but it seems as if they aren't correct. #5. Alex is creating a rectan

Algebra ->  College  -> Linear Algebra -> SOLUTION: I have done 7/10 of my homework. I will submit each one separately. The answers are randomized on the back, but it seems as if they aren't correct. #5. Alex is creating a rectan      Log On


   



Question 643880: I have done 7/10 of my homework. I will submit each one separately.
The answers are randomized on the back, but it seems as if they aren't correct.
#5. Alex is creating a rectangular garden that has an area of 456 ft squared. If the length of the garden is 24 feet, what is the width of the garden?
I got 204 using 456= 2(24+w)

Answer by MathTherapy(10559) About Me  (Show Source):
You can put this solution on YOUR website!

I have done 7/10 of my homework. I will submit each one separately.
The answers are randomized on the back, but it seems as if they aren't correct.
#5. Alex is creating a rectangular garden that has an area of 456 ft squared. If the length of the garden is 24 feet, what is the width of the garden?
I got 204 using 456= 2(24+w)

It appears from what you did that you're think PERIMETER instead of AREA. The question gives the AREA as 456 sq ft.

Let width be W

A = LW

456 = 24(W)

456 = 24W

W, or width = 456%2F24, or highlight_green%2819%29 ft

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