SOLUTION: Help to solve 3x(2 - 6^0) - 9x = 5x^0 - absolute value of -9 - 6 end absolute vale -2(x-4^0)

Algebra ->  Absolute-value -> SOLUTION: Help to solve 3x(2 - 6^0) - 9x = 5x^0 - absolute value of -9 - 6 end absolute vale -2(x-4^0)      Log On


   

Question 64379This question is from textbook An Incremental Development
: Help to solve
3x(2 - 6^0) - 9x = 5x^0 - absolute value of -9 - 6 end absolute vale -2(x-4^0) This question is from textbook An Incremental Development

Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
3x(2 - 6^0) - 9x = 5x^0 - /-9 - 6/ -2(x-4^0)
[any number raised to a zero power equals (1)]
.
3x(2 - (1)) - 9x = 5(1) - /-9 - 6/ -2(x-(1))
3x(1) - 9x = 5 - /-15/ -2(x-1) [simplify]
3x - 9x = 5 - (+15) -2x+2)
-6x = 5 +15 -2x+2
-6x = 22 -2x
-6x+2x=22
-4x=22
x=-22/4
.
check by plugging x=-22/4 back into the original equation.