SOLUTION: (3k+4) to the 2nd power

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Question 643555: (3k+4) to the 2nd power
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%283k%2B4%29%5E2 Start with the given expression.


%283k%2B4%29%283k%2B4%29 Expand. Remember something like x%5E2=x%2Ax.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%283k%29%2B4%29%28highlight%283k%29%2B4%29 Multiply the First terms:%283%2Ak%29%2A%283%2Ak%29=9%2Ak%5E2.


%28highlight%283k%29%2B4%29%283k%2Bhighlight%284%29%29 Multiply the Outer terms:%283%2Ak%29%2A%284%29=12%2Ak.


%283k%2Bhighlight%284%29%29%28highlight%283k%29%2B4%29 Multiply the Inner terms:%284%29%2A%283%2Ak%29=12%2Ak.


%283k%2Bhighlight%284%29%29%283k%2Bhighlight%284%29%29 Multiply the Last terms:%284%29%2A%284%29=16.


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So we have the terms: 9%2Ak%5E2, 12%2Ak, 12%2Ak, 16


9%2Ak%5E2%2B12%2Ak%2B12%2Ak%2B16 Now add every term listed above to make a single expression.


9k%5E2%2B24k%2B16 Now combine like terms.


So %283k%2B4%29%5E2 FOILs to 9k%5E2%2B24k%2B16.


In other words, %283k%2B4%29%5E2=9k%5E2%2B24k%2B16.