SOLUTION: solve the homogeneous system: {2x+y+z=0 4x-5y+z=0 3x-2y+z=0

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: solve the homogeneous system: {2x+y+z=0 4x-5y+z=0 3x-2y+z=0       Log On


   



Question 64350: solve the homogeneous system: {2x+y+z=0
4x-5y+z=0
3x-2y+z=0

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
solve the homogeneous system:
2x+y+z=0..........................1
4x-5y+z=0....................2
3x-2y+z=0................3
EQN.2-EQN.1
2X-6Y=0......OR.......X-3Y=0........................4
EQN.3-EQN.1
X-3Y=0......................5
EQN.4 & EQN.5 ARE IDENTICAL.HENCE THE SYSTEM IS CONSISTENT AND DEPENDENT.
SO SOLUTION SET IS
FROM EQN.4
X=3Y
PUTTING IN EQN.1
6Y+Y+Z=0
7Y+Z=0
Z=-7Y...
HENCE ANY SET OF THE TYPE
3Y,Y,-7Y....FOR ANY VALUE OF Y IS A SOLUTION SET..EX...(3,1,-7),(9,3,-21)...ETC..