SOLUTION: Im confused on how to solve this problem.. {{{(2/(x+1))}}} < or equal to {{{(3/(x-1))}}} Thank you!

Algebra ->  Inequalities -> SOLUTION: Im confused on how to solve this problem.. {{{(2/(x+1))}}} < or equal to {{{(3/(x-1))}}} Thank you!      Log On


   

Question 643498: Im confused on how to solve this problem..
%282%2F%28x%2B1%29%29 < or equal to %283%2F%28x-1%29%29
Thank you!
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
%282%2F%28x%2B1%29%29+%3C+=%283%2F%28x-1%29%29

%282%2F%28x%2B1%29%29+-%283%2F%28x-1%29%29%3C+=0

%282%28x-1%29-3%28x%2B1%29%29%2F%28%28x-1%29%28x%2B1%29%29%3C=0

%282x-2-3x-3%29%2F%28%28x-1%29%28x%2B1%29%29%3C=0

%28-5-x%29%2F%28%28x-1%29%28x%2B1%29%29%3C+=0

%28-5-x%29%2F%28x%5E2-1%29%3C+=0

-1%28x%2B5%29%2F-1%281-x%5E2%29%3C=0

%28x%2B5%29%2F%281-x%5E2%29%3C=0

solutions:
x%3E1 and x%3E=5
or
-5%3C=x%3C1