Question 643461: I'm trying to solve excuse the way I write this problem I don't know any other way. 2 squared+3x(6- 2)squared is outside of perrenthesis. I have tried to do it like this. 2x2+3x(6-2)squared then 4+3x4x4then7x16 and came up with 112
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! it's kind of tough to understand the problem the way it is written.
let me try the following:
your problem is 2^2 + 3(6-2)^2
this means the number 2 is squared and then it is being added to the expression of (6-2) which is squared and then multiplied by 3.
you used x's which i think was intended to show multiplication.
if so, don't use x because it gets confused with the variable with the name of x.
use *.
that is the traditional symbol to indicate multiplication.
^ is the traditional symbol to indicate raising something to an exponent.
with this notation, your problem appears to be:
2^2 + 3*(6-2)^2
you need to resolve the expression within the parentheses first.
since 6-2 = 4, your expression becomes:
2^2 + 3*4^2
you need to do exponentiation before multiplication.
2^2 = 4
4^2 = 16
your expression becomes:
4 + 3*16
you need to do multiplication next.
3*16 = 48
your expression becomes:
4 + 48
you do addition last.
4 + 48 = 52
your answer is 52 if i understood your problem correctly.
order of operations is important.
order of operations is:
going from left to right.
1. resolve all expressions within parentheses.
2. resolve exponents and roots first
3. resolve multiplies and divides next.
4. resolve adds and subtracts next.
you always resolve the most inner set of parentheses first.
you always use steps 2, 3, and 4, to resolve expressions within a set of parentheses.
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